Physics - Magnetism Question with Solution | TestHub

Since, the radius of circular path of a charged particle in magnetic field is $\mathrm{r}=\frac{\mathrm{mv}}{\mathrm{qB}}=\frac{\rho }{\mathrm{qB}}$ Now, the radius of circular path of charged particle of given momentum $\rho$ and magnetic field $\mathrm{B}$ is given by $\mathrm{r}\propto \frac{1}{\mathrm{q}}$ But charge on both charged particles, protons and deuterons, is same. Therefore, $$\frac{{\mathrm{r}}_{\mathrm{p}}}{{\mathrm{r}}_{\mathrm{D}}}=\frac{{\mathrm{q}}_{\mathrm{D}}}{{\mathrm{q}}_{\rho }}=\frac{1}{\mathrm{l}}$$