Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic torque & energyHard2 minPYQ_2018
PhysicsHardnumerical

A moving coil galvanometer has 50 turns and each turn has an area2×10-4 m2. The magnetic field produced by the magnet inside the galvanometer is0.02 T. The torsional constant of the suspension wire is10-4 N m rad-1. When a current flows through the galvanometer, a full scale deflection occurs if the coil rotates by0.2 rad. The resistance of the coil of the galvanometer is50 Ω. This galvanometer is to be converted into an ammeter capable of measuring current in the range0-1.0 A. For this purpose, a shunt resistance is to be added in parallel to the galvanometer. The value of this shunt resistance, in ohms, is __________.

Answer:
5.55
Solution:

n=50 turnsA=2×10-4 m2
B=0.02TK=10-4
Qm=0.2 radRg=50Ω
IA=0-1.0Aτ=MB=Cθ, M=NIA 
B I g NA=Cθ
0.02× I g ×50×2×10-4=10-4×0.2
Ig=0.1A
For galvanometer, resistance is to be connected to ammeter in shunt.

Ig×Rg=I-IgS
0.1×50=1-0.1S
S=509=5.55

Stream:JEE_ADVSubject:PhysicsTopic:MagnetismSubtopic:Magnetic torque & energy
2mℹ️ Source: PYQ_2018

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