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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMotion analysis in electric & magnetic fieldEasy2 minPYQ_2020

PhysicsEasysingle choice

If a magnet is suspended at an angle $30 °$ to the magnet meridian, the dip of the needle makes an angle of $45 °$ with the horizontal, the real dip is

Options:

Answer:

Solution:

$\tan δ^{'} = \frac{\tan δ}{\cos θ} = \frac{\tan 45^{o}}{\cos 30^{o}}$

$\tan δ = \frac{1}{\sqrt{3} / 2}$

$= \frac{2}{\sqrt{3}}$

$δ = \tan^{- 1} (\frac{2}{\sqrt{3}})$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:MagnetismSubtopic:Motion analysis in electric & magnetic field

⏱ 2mℹ️ Source: PYQ_2020

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