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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMagnetic Dipole & MomentHard2 minPYQ_2016

PhysicsHardsingle choice

A particle of charge $q$ and mass $m$ moves in a circular orbit of radius $r$ with angular speed $ω$ . The ratio of the magnitude of its magnetic moment to that of its angular momentum depends on

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Solution:

The angular momentum $L$ of the particle is given by $L = m r^{2} ω$ where $ω = 2 πn$ $∴$ Frequency $n = \frac{ω}{2 π}$ ; Further $i = q \times n = \frac{ω q}{2 π}$ Magnetic moment, $M = i A = \frac{ω q}{2 π} \times π r^{2}$ ; $∴ M = \frac{ω q r ^{2}}{2}$ So, $\frac{M}{L} = \frac{ω q r ^{2}}{2 m r ^{2} ω} = \frac{q}{2 m}$

Stream:VITEEESubject:PhysicsTopic:MagnetismSubtopic:Magnetic Dipole & Moment

⏱ 2mℹ️ Source: PYQ_2016

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