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Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawMedium2 minPYQ_2014

PhysicsMediumsingle choice

Two identical long conducting wires $A O B$ and $C O D$ are placed at right angle to each other, with one above other such that ‘ $O$ ’ is their common point for the two. The wires carry $I_{1}$ and $I_{2}$ currents, respectively. Point ‘ $I$ ’ is lying at distance ‘ $d$ ’ from ‘ $O$ ’ along a direction perpendicular to the plane containing the wires. The magnetic field at the point ‘ $P$ ’ will be:NEET 2014

Options:

Answer:

Solution:

$\vec{B}$ due to wire $(1) {\vec{B}}_{1} = (\frac{μ_{0} i_{1}}{2 π d}) \hat{i}$
$\vec{B}$ due to wire $(2) {\vec{B}}_{2} = (\frac{μ_{0} i_{2}}{2 π d}) (- \hat{j})$
$|B_{n e t}| = \frac{μ_{0}}{2 π d} \sqrt{i_{1}^{2} + i_{2}^{2}}$

Stream:NEETSubject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: PYQ_2014

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