Two long straight parallel wires, carrying (adjustable) currents I 1 and I 2 , are kept at a distance d apart. If the force F between the two wires is taken as 'positive' when the wires repe

Question

Two long straight parallel wires, carrying (adjustable) currents I 1 and I 2 , are kept at a distance d apart. If the force F between the two wires is taken as 'positive' when the wires repel each other and 'negative' when the wires attract each other, the graph showing the dependence of F , on the product I 1 I 2 , would be:

TestHub · Accepted Answer

Force between two parallel current carrying wires is given as

$f = \frac{μ_{0} I_{1} I_{2}}{2 π d} l$

$F \propto I_{1} I_{2}$

When $I_{1}, I_{2}$ are in same direction the $I_{1} I_{2} is + v e$ ⇒ attraction ⇒ -ve

When $I_{1} I_{2}$ are in opposite direction then

$I_{1} I_{2} = - v e$

$∴$ Force = repulsive = +ve

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