Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismMotion analysis in electric & magnetic fieldHard2 minQB
PhysicsHardnumerical

A proton with a kinetic energy of2.0 eVmoves into a region of uniform magnetic field of magnitudeπ2×10-3 T. The angle between the direction of magnetic field and velocity of proton is60o. The pitch of the helical path taken by the proton is ____cm. (Take, mass of proton=1.6×10-27 kgand charge on proton=1.6×10-19 C).

Answer:
40.00
Solution:

The given data is

K.E=2 eV

B=π2×10-3 T

θ=60o

The pitch of the proton is given by

P=2πmqB×vcosθ   ...(i)

By using

 K=mv22⇒v=2Km

Substituting the values in equation (i)

=2π×2mKE×12×21.6×10-19×π×10-3

=2×2×1.6×10-27×2×1.6×10-19×1031.6×10-19

=2×2×10–1=0.4 m

Stream:JEESubject:PhysicsTopic:MagnetismSubtopic:Motion analysis in electric & magnetic field
⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...