Physics - Magnetism Question with Solution | TestHub

PhysicsMagnetismBiot-savart's & Ampere's Circuital lawEasy2 minPYQ_2016

PhysicsEasysingle choice

A long wire carrying a steady current is bent into a circular loop of one turn. The magnetic field at the centre of the loop is $B .$ It is then bent into a circular coil of $n$ turns. The magnetic field at the centre of this coil of $n$ turns will beNEET 2016 (Phase 2)

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Answer:

Solution:

$B = \frac{μ_{0} I}{2 r}$ .

When $n$ turns are made, radius becomes $r^{'}$ .

$n \times 2 π r^{'} = 2 π r \Rightarrow r^{'} = \frac{r}{n}$ .

Now, $B^{'} = \frac{μ_{0} n I}{2 r^{'}} = n^{2} \frac{μ_{0} I}{2 r} = n^{2} B$ .

Stream:NEETSubject:PhysicsTopic:MagnetismSubtopic:Biot-savart's & Ampere's Circuital law

⏱ 2mℹ️ Source: PYQ_2016

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