A massless spring gets elongated by amount x 1 under a tension of 5 N . Its elongation is x 2 under the tension of 7 N . For the elongation of ( 5 x 1 − 2 x 2 ) , the tension in the spring wil

Question

A massless spring gets elongated by amount $x_{1}$ under a tension of 5 N . Its elongation is $x_{2}$ under the tension of 7 N . For the elongation of $(5 x_{1} - 2 x_{2})$ , the tension in the spring will be,

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Answer:

C

Solution:

$kx_{1} = 5 N kx_{2} = 7 N k (5 x_{1} - 2 x_{2}) = 5 kx_{1} - 2 kx_{2} = 5 \times 5 - 2 \times 7 = 11 N$

TestHub · Accepted Answer

​ kx 1 ​ = 5 N kx 2 ​ = 7 N k ( 5 x 1 ​ − 2 x 2 ​ ) = 5 kx 1 ​ − 2 kx 2 ​ = 5 × 5 − 2 × 7 = 11 N ​

Physics - Laws of Motion Question with Solution | TestHub

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