Physics - NLM Question with Solution | TestHub

Let the velocity of the ball just when it leaves the hand is $u$ then applying, $\begin{array}{l}{v}^2-u^2=2a\text{ for upward journey }\\ \Rightarrow -u^2=2(-10)\times 2\\ \Rightarrow u^2=40\end{array}$ Again applying $v^2-u^2=2as$ for the upward journey of the ball, when the ball is in the hands of the thrower, $\begin{array}{l}{v}^2-u^2=2as\\ \Rightarrow 40-0=2(a)0.2\\ \Rightarrow a=100\mathrm{m}/{\mathrm{s}}^2\\ \therefore \mathrm{F}=ma=0.2\times 100=20\mathrm{N}\\ \Rightarrow \mathrm{N}-mg=20\\ \Rightarrow \mathrm{N}=20+2=22\mathrm{N}\end{array}$