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PhysicsKinematics2-D & 3DHard2 minQB

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Passage / Comprehension

An insect I crosses a cylinder of radius R with minimum jumping speed. Path of the insect is shown in figure. When insect will be just touching the cylinder at C \& D its velocity will be tangent to the cylinder at that point. At point C radius of the cylinder is making an angle $α$ from the vertical. Minimum velocity of insect is u , at an angle $θ$ from the horiozntal $[$ Given : $R = \frac{2 ( 2 - 1 )}{10} m & g = 10 m / s^{2}]$

Value of minimum velocity $u$ in $m / s$ is

Options:

Answer:

Solution:

$u_{min} = gR [2 + 2 \times \frac{1}{2} + 2] = 2 gR (1 + 2)$

$= 2 \times 10 \times \frac{2 ( 2 - 1 )}{10} \times (1 + 2) = 2 ms^{- 1}$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:2-D & 3D

⏱ 2mℹ️ Source: QB

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