Physics - Kinematics Question with Solution | TestHub

A particle is projected at an angle of $60^{\circ }$ with the horizontal with a speed of $10\sqrt{3}$ m/s from point $A$ as shown. At the same time the sufficiently long wedge is made to move with constant velocity of $10\sqrt{3}$ m/s towards right as shown in figure-1.137. The time in seconds after which the particle will hit the wedge will be ($g=10$ $m/s^2$):