Physics - Kinematics Question with Solution | TestHub

Range on level ground is proportional to the sine of twice the launch angle.

$$R(15^{\circ })=\frac{u^2}{g}\sin 30^{\circ }=100\sqrt{3}\mathrm{m}$$

$$\frac{u^2}{g}=200\sqrt{3}\mathrm{m}$$

Sixty degrees with the vertical means thirty degrees with the horizontal.

$$R(30^{\circ })=200\sqrt{3}\sin 60^{\circ }=300\mathrm{m}$$

Option C.