Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DEasy2 minQB

PhysicsEasysingle choice

Starting from rest, a particle moving along a straight line is accelerated by the acceleration :

Answer:

Solution:

$v = \int_{0}^{2} (4 - t^{2}) d t + \int_{2}^{4} \frac{1}{3} d t$

$= [4 t - \frac{t ^{3}}{3}]_{0}^{2} + \frac{1}{3} [4 - 2] = 4 \times 2 - \frac{8}{3} + \frac{2}{3} = 8 - 2 = 6 m / s$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: QB

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