A particle starts from rest and moves as shown in the acceleration-time graph (figure-1.104): $a = + 3 m / s^{2}$ for the first 2 s and $a = - 3 m / s^{2}$ for the next 2 s. The correct velocity-time graph for the interval of 4 seconds is:

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The velocity increases linearly from 0 to 6 m / s during the first 2 s (constant positive acceleration) and then decreases linearly, reaching zero at t = 4 s. Only graph (A) shows this symmetric triangle. Option A.

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