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Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics2-D & 3DHard2 minQB

PhysicsHardinteger

A particle moves along the parabolic path $x = y^{2} + 2 y + 2$ in such a way that y-component of velocity $2 m / s$ is constant during the complete motion, Find the magnitude of acceleration (in $m / s^{2}$ ).

Answer:

Solution:

$x = y^{2} + 2 y + 2$

$\frac{d x}{d t} v_{x} a_{x} = 2 x \frac{d y}{d t} + 2 \frac{d y}{d t} = 4 y + 4 = \frac{d v _{x}}{d t} = 4 \frac{d y}{d t} = 4 \times 2 = 8 m / s^{2}$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:2-D & 3D

⏱ 2mℹ️ Source: QB

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