Physics - Kinematics Question with Solution | TestHub

PhysicsKinematicsRelativeEasy2 minPYQ_2020

PhysicsEasysingle choice

A particle is projected at an angle of $60 °$ above the horizontal with a speed of $10 m s^{- 1}$ . After some time the direction of its velocity makes an angle of $30 °$ above the horizontal. The speed of the particle at this instant is

Options:

Answer:

Solution:

Let $v$ be the velocity of point where it make angle $30^{ο}$ with
horizontal
thus , horizontal velocity remains uncharged, so

$v cos 30^{ο} = 10 cos 60^{ο}$

$v \frac{\sqrt{3}}{2} = \frac{10}{2}$

$v = \frac{10}{\sqrt{3}} m s^{- 1}$

Subject:PhysicsTopic:KinematicsSubtopic:Relative

⏱ 2mℹ️ Source: PYQ_2020

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