Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DHard2 minPYQ_2019

PhysicsHardsingle choice

A particle is moving with speed $v = b \sqrt{x}$ along positive $x -$ axis. Calculate the speed of the particle at time $t = τ$ (assume that the particle is at origin at $t = 0$ )

Options:

Answer:

Solution:

$v = b \sqrt{x}$ … (1)
$\Rightarrow \frac{d x}{d t} = b \sqrt{x}$
$\frac{d x}{\sqrt{x}} = b d t$
$\int_{0}^{x} \frac{d x}{\sqrt{x}} = \int_{0}^{t} b d t$
$2 \sqrt{x} = b t$ … (2)
From equation (1) and (2)
$v = b (\frac{b t}{2})$
$∴ a t t = τ$
$v = \frac{b^{2} τ}{2}$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: PYQ_2019

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