Physics - Kinematics Question with Solution | TestHub

$x_A=6t-3$

$v_A=\frac{d}{dt}\left(6t-3\right)=6$

Particle A moves with constant velocity.

$v_B=\frac{d}{dt}\left(4t^2-2t+3\right)=8t-2, a_B=\frac{d}{dt}\left(8t-2\right)=8$

Particle B moves with constant acceleration

$v_C=\frac{d}{dt}\left(3t^3-2t^2+t-7\right)=9t^2-4t+1$

$a_C=18t-4$

So, the particle moves with variable acceleration.

$x_D=7\cos {60}^o-3\sin {30}^o$

Since$x_D$does not depend upon time therefore particle is at rest.