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PhysicsKinematics1-DEasy2 minPYQ_2020

PhysicsEasynumerical

An athlete, initially at rest, takes $2 s$ to reach his maximum speed of $36 km h^{- 1}$ . The magnitude of his average acceleration (in $m s^{-2}$ ) is

Answer:

5.00

Solution:

The final speed of the athlete, $v = 36 km h^{- 1} = 36 \times \frac{5}{18} = 10 m s^{- 1}$

initial speed, $u = 0$

time taken $t = 2 s$

for average acceleration, $a$

$v = u + a t$

$a = \frac{v - u}{t} = \frac{10 - 0}{2} = 5 m s^{- 2}$

Stream:NTA_ABHYASSubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: PYQ_2020

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