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PhysicsKinematics1-DEasy2 minPYQ_2024
PhysicsEasysingle choice

Position of an ant ( S in metres) moving in Y-Z plane is given by S=2t2j^+5k^ (where t is in second). The magnitude and direction of velocity of the ant at t=1 s will be :

Options:

Answer:
D
Solution:

The velocity of the ant can be found as follows:

v=dSdt=ddt2t2j^+5k^=4tj^   ...1

At t=1 s, from equation (1), it follows that

v=4j^

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D
2mℹ️ Source: PYQ_2024

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