Physics - Heat & Thermo Question with Solution | TestHub

Warm the ice to $0^{\circ }\mathrm{C}$, melt it, warm the water to $100^{\circ }\mathrm{C}$, then vaporize it (all masses in g):
$$Q=10^3\times 0.5\times (0-(-10))+80\times 10^3+10^3\times 1\times (100-0)+540\times 10^3$$
$$Q=5000+80000+100000+540000$$
$$Q=725000\text{cal}=725\text{kcal}$$