A steam engine intakes 50 g of steam at 100 ° C per minute and cools it down to 20 ° C . If latent heat of vaporization of steam is 540 cal g - 1 , then the heat rejected by the steam engine per minut

Question

A steam engine intakes 50 g of steam at 100 ° C per minute and cools it down to 20 ° C . If latent heat of vaporization of steam is 540 cal g - 1 , then the heat rejected by the steam engine per minute is _____ × 10 3 cal (Given : specific heat capacity of water : 1 cal g - 1 C ∘ - 1 )

TestHub · Accepted Answer

Heat rejected by the steam engine per minute will be equal to latent heat per minute plus heat rejected by the water to cool down.

$\frac{∆ H}{∆ t} = \frac{∆ m}{∆ t} L + \frac{∆ m}{∆ t} s ∆ T \Rightarrow \frac{∆ H}{∆ t} = 50 \times 540 + 50 \times 1 \times 80 = 31000 cal \min^{- 1} = 31 \times 10^{3} cal \min^{- 1}$

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