A calorimeter containing first 40 g and then 100 g of water is heated and suspended in the same constant temperature enclosure. It is found that the time to cool from 5 0 ∘ C to 4 0 ∘ C in the two cas

Question

A calorimeter containing first 40 g and then 100 g of water is heated and suspended in the same constant temperature enclosure. It is found that the time to cool from 5 0 ∘ C to 4 0 ∘ C in the two cases was 15 and 33 min respectively. Calculate the water equivalent of the calorimeter.

TestHub · Accepted Answer

Let the water equivalent be w . Rate of heat loss is the same in both cases, so: ( m w ​ × S w ​ + w × S w ​ ) Δ t Δ T ​ = constant ( 40 + w ) × 15 10 ​ = ( 100 + w ) × 33 10 ​ 11 ( 40 + w ) = 5 ( 100 + w ) 440 + 11 w = 500 + 5 w 6 w = 60 w = 10 gm

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