If the coefficient of conductivity of aluminium is 0.5 cal c m − 1 s − 1 ∘ C − 1 , then in order to conduct 10 cal s − 1 c m − 2 in the steady state, the temperature gradient in aluminium must be:

A t Q = K d x d T , so d x d T = 0.5 10 = 2 0 ∘ C/cm. C.

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoHeat TransferMedium2 min

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If the coefficient of conductivity of aluminium is 0.5 cal $c m^{- 1}$ $s^{- 1}$ $^{\circ}$ $C^{- 1}$ , then in order to conduct 10 cal $s^{- 1}$ $c m^{- 2}$ in the steady state, the temperature gradient in aluminium must be:

Options:

Answer:

Solution:

$\frac{Q}{A t} = K \frac{d T}{d x}$ , so $\frac{d T}{d x} = \frac{10}{0.5} = 2 0^{\circ}$ C/cm. C.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Heat Transfer

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