In a calorimeter, 20 grams of liquid water at 100 ∘ C is mixed with 50 grams of steam at 100 ∘ C . The system is allowed to come to equilibrium. Assuming that heat exchanged between the calorimeter an

Question

In a calorimeter, 20 grams of liquid water at 100 ∘ C is mixed with 50 grams of steam at 100 ∘ C . The system is allowed to come to equilibrium. Assuming that heat exchanged between the calorimeter and the surroundings can be ignored, which of the following best describes the net energy exchange between the steam and the liquid during the process of coming to equilibrium ?

TestHub · Accepted Answer

Both steam and water are at the same temperature, $100^{\circ} C$ .
With the usual saturated two-phase equilibrium assumption, no temperature difference drives heat transfer.
There is no net energy exchange between them.

Physics - Heat & Thermo Question with Solution | TestHub

Options:

Doubts & Discussion