Physics - Heat & Thermo Question with Solution | TestHub

An ideal gas is trapped inside a test tube of cross-sectional area$20\times 10^{-6}$m${}^2$as shown in the figure.

The gas occupies a height$L_1$at the bottom of the tube and is separated from air at atmospheric pressure by a mercury column of mass 0.002 kg. If the tube is quickly turned isothermally, upside down so that mercury column encloses the gas from below. The gas now occupies height$L_2$in the tube. The ratio$\frac{L_2}{L_1}$is [Take atmospheric pressure =$10^5$Nm${}^{-2}$]