100 kg solid iron at 73 0 ∘ C is cooled by immersing it into vessel filled by water at 1 5 ∘ C . In the process, final temperature of water is 8 0 ∘ C . How much was mass of water? (Neglect vaporisati

Question

100 kg solid iron at 73 0 ∘ C is cooled by immersing it into vessel filled by water at 1 5 ∘ C . In the process, final temperature of water is 8 0 ∘ C . How much was mass of water? (Neglect vaporisation) S w a t er ​ = 4200 J/kg ∘ C , S i ro n ​ = 420 J/kg ∘ C .

TestHub · Accepted Answer

Heat lost by the iron = heat gained by the water: 100 × 420 × ( 730 − 80 ) = m × 4200 × ( 80 − 15 ) 100 × 420 × 650 = m × 4200 × 65 m = 4200 × 65 100 × 420 × 650 ​ m = 100 kg

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