A bullet of mass 5 gram , travelling with a speed of 210 m s - 1 strikes a fixed wooden target. One half of its kinetic energy is converted into heat in the wood. The rise of temperature of the bullet

Question

A bullet of mass 5 gram , travelling with a speed of 210 m s - 1 strikes a fixed wooden target. One half of its kinetic energy is converted into heat in the wood. The rise of temperature of the bullet if the specific heat of its material is 0 . 030 gram ° C - 1 1 calorie = 4 .2 × 10 7 ergs close to :

TestHub · Accepted Answer

As per given condition Half of kinetic energy is transferred into heat energy and raises the temperature of bullet

$\frac{1}{2} \times \frac{1}{2} m v^{2} = m s Δ T$

$Δ t = \frac{V^{2}}{4 s}$

$= \frac{210 \times 210}{4 \times 4.2 \times 0.3 \times 1000} = 87.5 ° C$

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