A bicycle tyre is filled with air having pressure of 270 kPa at 2 7 ∘ C . The approximate pressure of the air in the tyre when the temperature increases to 3 6 ∘ C is

From the ideal gas equation PV = nRT Here, volume is constant ∴ T 1 P 1 = T 2 P 2 Here, T 1 = 27 + 273 = 300 K P 1 = 270 kPa T 2 = 36 + 273 = 309 K ⇒ P 2 = T 1 P 1 × T 2 = 300 270 × ( 309 ) = 278 kPa

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PhysicsHeat & ThermoDifferent processesEasy2 minPYQ_2023

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A bicycle tyre is filled with air having pressure of $270 kPa$ at $2 7^{\circ} C$ . The approximate pressure of the air in the tyre when the temperature increases to $3 6^{\circ} C$ is

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From the ideal gas equation $PV = nRT$ Here, volume is constant $∴ \frac{P _{1}}{T _{1}} = \frac{P _{2}}{T _{2}}$
Here, $T_{1} = 27 + 273 = 300 K$
$P_{1} = 270 kPa$
$T_{2} = 36 + 273 = 309 K$
$\Rightarrow P_{2} = \frac{P _{1}}{T _{1}} \times T_{2} = \frac{270 \times ( 309 )}{300} = 278 kPa$

Stream:BITSATSubject:PhysicsTopic:Heat & ThermoSubtopic:Different processes

⏱ 2mℹ️ Source: PYQ_2023

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