2 moles of an ideal monoatomic gas occupying volume V is adiabatically expanded from temperature 300K to a volume of 2 2 V . Then the final temperature & change in internal energy are respectively (

Question

2 moles of an ideal monoatomic gas occupying volume V is adiabatically expanded from temperature 300K to a volume of 2 2 ​ V . Then the final temperature & change in internal energy are respectively ( R = 8.3 )

TestHub · Accepted Answer

In adiabatic process, TV γ − 1 = constant T 2 ​ = ( V 2 ​ V 1 ​ ​ ) γ − 1 × T 1 ​ = ( 2 2 ​ V V ​ ) 3 5 ​ − 1 × 300 = 150 K or − 12 3 ∘ C Change in internal energy Δ U = μ C V ​ dt Δ U = 2 × 2 3 ​ R × ( 150 − 300 ) = 3 × 8.3 × ( − 150 ) = − 3735 joule

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