Physics - Gravitation Question with Solution | TestHub

The acceleration due to gravity at a latitude $\lambda$ is ${\mathrm{g}}^{\prime }=\mathrm{g}-\mathrm{R}{\omega }^2{\cos }^2\lambda$ At the poles, $\lambda =90^{\circ }$ $\therefore {\mathrm{g}}^{\prime }=\mathrm{g}={\mathrm{g}}_{\mathrm{p}}$ For $\lambda =60^{\circ }$, ${\mathrm{g}}^{\prime }={\mathrm{g}}_{\mathrm{p}}-\mathrm{R}{\omega }^2{\cos }^2\lambda$ or $g^{\prime }=g_p-R{\omega }^2{\cos }^{2}60^{\circ }$ $=g_p-R{\omega }^2{\left(\frac{1}{2}\right)}^2=g_p-\frac{1}{4}R{\omega }^2$