Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationEnergy & PotentialEasy2 minPYQ_2024

PhysicsEasysingle choice

The kinetic energy of a satellite in its orbit around the earth is E . What should be the kinetic energy of the satellite so as to enable it to escape from the gravitational pull of the earth?

Options:

Answer:

Solution:

We know that $v_{e} = 2 v_{0}$ , where $v_{0}$ is orbital velocity. K.E. in the orbit, $E = \frac{1}{2} M v_{0}^{2}$ K.E. to escape $E = \frac{1}{2} M v_{e}^{2} = \frac{1}{2} M (2 v_{0}^{2})$ $= \frac{1}{2} M v_{0}^{2} \times 2 = 2 E$

Stream:BITSATSubject:PhysicsTopic:GravitationSubtopic:Energy & Potential

⏱ 2mℹ️ Source: PYQ_2024

Doubts & Discussion

Loading discussions...