The depth ' d ' below the surface of the earth where the value of acceleration due to gravity becomes ( n 1 ) times the value at the surface of the earth is ( R = radius of the earth)

Inside the earth, g ′ = g ( 1 − R d ) n g = g ( 1 − R d ) Or d = R ( n n − 1 )

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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationField & ForceEasy2 minPYQ_2021

PhysicsEasysingle choice

The depth ' $d$ ' below the surface of the earth where the value of acceleration due to gravity becomes $(\frac{1}{n})$ times the value at the surface of the earth is $(R$ = radius of the earth)

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Solution:

Inside the earth, $g^{'} = g (1 - \frac{d}{R})$ $\frac{g}{n} = g (1 - \frac{d}{R})$ Or $d = R (\frac{n - 1}{n})$

Stream:MHT_CETSubject:PhysicsTopic:GravitationSubtopic:Field & Force

⏱ 2mℹ️ Source: PYQ_2021

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