Physics - Gravitation Question with Solution | TestHub

Key Idea : Kinetic energy of satellite is half of its potential energy. Potential energy of satellite $U=-\frac{G{M}_{e}m}{R_e}$ where $R_e$ is radius of earth, $M_e$ the mass of earth, $m$ the mass of satellite and $G$ the gravitational constant. $|U|=\frac{G{M}_{e}m}{R_e}$ Kinetic energy of satellite $K=\frac{1}{2}\frac{G{M}_{e}m}{R_e}$ Thus,$\frac{K}{|U|}=\frac{1}{2}\frac{G{M}_{e}m}{R_e}\times \frac{R_e}{G{M}_{e}m}=\frac{1}{2}$