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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationField & ForceEasy2 minPDF

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The value of acceleration due to gravity is $g_{1}$ at a height $h = \frac{R}{2}$ ( $R =$ radius of the earth) from the surface of the earth. It is again equal to $g_{1}$ and a depth d below the sur-face of the earth. Assume Earth has uniform density. The ratio $(\frac{d}{R})$ equals :

Options:

Answer:

Solution:

Under the uniform-density Earth approximation:

$g_{h} = g (\frac{R}{R + h})^{2} = \frac{4}{9} g$

$g_{d} = g (1 - \frac{d}{R})$

$1 - \frac{d}{R} = \frac{4}{9}$

$\frac{d}{R} = \frac{5}{9}$

Answer B.

Stream:JEESubject:PhysicsTopic:GravitationSubtopic:Field & Force

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