Physics - Gravitation Question with Solution | TestHub

Orbital velocity of satellite $=v_0$ and escape velocity from the earth $=v_e$. We have orbital velocity $\left(v_0\right)=\sqrt{gR}$ and escape velocity $\left(v_e\right)=\sqrt{2gR}$ Therefore ratio of orbital velocity to escape velocity $$\frac{v_o}{v_e}=\sqrt{\frac{gR}{2gR}}=\frac{1}{\sqrt{2}}\text{ or }{v}_e=\sqrt{2}{v}_0\text{. }$$