A light ray incident on the reflecting surface y = 2 x 2 is deviated through 6 0 ∘ due to reflection at point P as shown in the figure. Find the coordinates of point P.

Using tan 6 0 ∘ with the slope of the tangent at P.

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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsReflection at curved surfaceMedium2 minQB

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A light ray incident on the reflecting surface $y = 2 x^{2}$ is deviated through $6 0^{\circ}$ due to reflection at point P as shown in the figure. Find the coordinates of point P.

Options:

Answer:

Solution:

Using $tan 6 0^{\circ}$ with the slope of the tangent at P.

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Reflection at curved surface

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