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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsOptical instrumentsMedium2 minQB

PhysicsMediumsingle choice

The focal length of the objective and the eyepiece of a telescope are 50 cm and 5 cm respectively. If the telescope is focussed for distinct vision on a scale distant 2 m from its objective, then its magnifying power will be:

Options:

Answer:

Solution:

Objective: $u = - 200 cm, 1/ v = 1/50 - 1/200 \Rightarrow v = 200/3 cm, m_{o} = - 1/3$ . Eyepiece at distinct vision: $m_{e} = 1 + D / f_{e} = 1 + 25/5 = 6$ .

$m = - (1/3) \times 6 = - 2.$

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Optical instruments

⏱ 2mℹ️ Source: QB

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