Physics - Geometrical Optics Question with Solution | TestHub

The image is at $(-1,0,0)$.

It is seen only from points inside the cone from the image through the mirror edge.

The mirror radius 1 m at distance 1 m from the image gives a half-angle of 45°.

At distance $x+1$ from the image the field radius is $x+1:2\mathrm{m}$ at $x=1$ and 3 m at $x=2$. $(2,2,2)$ : radius $\sqrt{8}=2.83<3$ inside. $(1,-1,1.5):1.80<2$ inside.

(1, 1.5, 1.5): $2.12>2$ outside.

(-0.5, 0, 0.5) is behind the mirror.

Ans. (B), (D)