Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction+ReflectionEasy2 minPYQ_2020

PhysicsEasysingle choice

A biconvex lens of focal length $f_{1} = 10 cm$ is placed $40 cm$ in front of a concave mirror of focal length $f_{2} = 7.50 cm,$ as shown in the figure. An object, $2 cm$ high, is placed $20 cm$ to the left of the lens.

The image formed by the lens, as rays travel to the right, is

Options:

Answer:

Solution:

From lens equation,

$\frac{1}{v} - \frac{1}{(- 20)} = \frac{1}{10} \Rightarrow v = + 20 cm$

Magnification, $m_{1} = \frac{v}{u} = (\frac{+ 20}{- 20}) = - 1$

Image is real, inverted, and same size as object.

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction+Reflection

⏱ 2mℹ️ Source: PYQ_2020

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