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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A $90 °$ corner is made from a transparent optical material with a refractive index such that $A$ cannot see $B$ when he is standing behind the corner. Minimum value of refractive index is

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Answer:

Solution:

$r_{m i n} > θ_{c}$

$r = 90 - β$

$r$ is minimum when $β$ is maximum.

The maximum value of $β$ is $θ_{c}$

$∴ 90^{o} - θ_{c} > θ_{c}$

$45^{o} > θ_{c}$

$\Rightarrow \frac{1}{\sqrt{2}} > \frac{1}{μ}$

$\Rightarrow μ > \sqrt{2}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Geometrical OpticsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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