Physics - Geometrical Optics Question with Solution | TestHub

Given object distance $u=-15$ cm and focal length $f=-10$ cm.

Using the mirror formula:

$\frac{1}{v}+\frac{1}{u}=\frac{1}{f}$

$\frac{1}{v}-\frac{1}{15}=-\frac{1}{10}$

$\frac{1}{v}=\frac{1}{15}-\frac{1}{10}=\frac{2-3}{30}=-\frac{1}{30}$

$v=-30$ cm

Magnification $m=-\frac{v}{u}=-\frac{-30}{-15}=-2$

Since $m$ is negative, the image is real and inverted. Since $|m|>1$, the image is magnified.

Answer: magnified and inverted