A ray of light travelling through glass of refractive index 2 , is incident on glass - air boundary at an angle of incidence 4 5 ∘ . If refractive index of air is 1 , then the angle of refraction will be [ sin 4 5 ∘ = 2 1 , sin 9 0 ∘ = 1 ]

(C) μ = 2 i = 4 5 ∘ μ i sin i = μ r sin r ⇒ 2 sin 4 5 ∘ = sin r ∴ r = 9 0 ∘

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Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at plane surfaceMedium2 minPYQ_2020

PhysicsMediumsingle choice

A ray of light travelling through glass of refractive index $2$ , is incident on glass - air boundary at an angle of incidence $4 5^{\circ}$ . If refractive index of air is 1 , then the angle of refraction will be $[sin 4 5^{\circ} = \frac{1}{2}, sin 9 0^{\circ} = 1]$

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Stream:MHT_CETSubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at plane surface

⏱ 2mℹ️ Source: PYQ_2020

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