Physics - Geometrical Optics Question with Solution | TestHub

Applying, Snell's law$\left(\mathrm{\mu sin}\left(\mathrm{i}\right)=\text{ constant }\right)$at$1$and$2$, we have



${\mu }_1{\text{sin i}}_1={\mu }_2{\text{sin i}}_2$

Here,${\mathrm{\mu }}_1={\mathrm{\mu }}_{\mathrm{glass}}, {\mathrm{i}}_1=\mathrm{i}$

$\therefore {\mathrm{\mu }}_2={\mathrm{\mu }}_{\text{air}}=1$and${\mathrm{i}}_2=90°$

$\therefore {\mathrm{\mu }}_{\mathrm{g}}\sin \left(\mathrm{i}\right)=1\times \sin 90°$

$\therefore \; {\mathrm{\mu }}_{\text{g}}=\frac{1}{\sin \left(\mathrm{i}\right)}$