A coin is kept at the bottom of a vessel having two immisible liquids having R.I. 3 4 and 3 5 and layer thickness 8 cm and 15 cm . Find apparent depth when it is seen normally (in cm .)

Question

A coin is kept at the bottom of a vessel having two immisible liquids having R.I. 3 4 ​ and 3 5 ​ and layer thickness 8 cm and 15 cm . Find apparent depth when it is seen normally (in cm .)

TestHub · Accepted Answer

The apparent depth is the sum of the apparent depths in each liquid.

Apparent depth in liquid 1: $\frac{R e a l d e pt h}{R e f r a c t i v e in d e x} = \frac{8}{\frac{4}{3}} = 8 \times \frac{3}{4} = 6$ cm

Apparent depth in liquid 2: $\frac{R e a l d e pt h}{R e f r a c t i v e in d e x} = \frac{15}{\frac{5}{3}} = 15 \times \frac{3}{5} = 9$ cm

Total apparent depth = $6 + 9 = 15$ cm

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