Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsTIR/Prism and DispersionMedium2 minQB

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The ratio of angle of minimum deviation produced by a thin prism ( $μ = 3/2$ ) in air to that in water is [ $μ_{w} = 4/3$ ]

Answer:

Solution:

In air: $δ = (μ - 1) A = 0.5 A$

In water: $δ^{'} = (\frac{μ}{μ _{w}} - 1) A = (\frac{9}{8} - 1) A = \frac{A}{8}$

$\frac{δ}{δ ^{'}} = 4$

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:TIR/Prism and Dispersion

⏱ 2mℹ️ Source: QB

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