Physics - Geometrical Optics Question with Solution | TestHub

PhysicsGeometrical OpticsRefraction at curved surface/LensHard2 minPYQ_2023

PhysicsHardnumerical

A point object $O$ is placed in front of two thin symmetrical coaxial convex lenses $L_{1}$ and $L_{2}$ with focal length $24 cm$ and $9 cm$ respectively. The distance between two lenses is $10 cm$ and the object is placed $6 cm$ away from lens $L_{1}$ as shown in the figure. The distance between the object and the image formed by the system of two lenses is _____________ $cm$

Answer:

34.00

Solution:

For $L_{1}$ :
$\frac{1}{v_{1}} + \frac{1}{6} = \frac{1}{24}$
$\Rightarrow \frac{1}{v_{1}} = \frac{1}{24} - \frac{1}{6}$
$= \frac{1 - 4}{24}$
$\Rightarrow \frac{1}{v_{1}} = (\frac{- 3}{24})$
$\Rightarrow v_{1} = - 8 cm$
For $L_{2}$ :
$u = - 18 cm$
$\Rightarrow \frac{1}{v} + \frac{1}{18} = \frac{1}{9}$
$\Rightarrow \frac{1}{v} = \frac{1}{9} - \frac{1}{18}$
$= \frac{2 - 1}{18}$
$\Rightarrow \frac{1}{v} = \frac{1}{18}$
$\Rightarrow v = 18 cm$
Distance between object and distance $= 16 + 18 = 34 cm$ .

Stream:JEESubject:PhysicsTopic:Geometrical OpticsSubtopic:Refraction at curved surface/Lens

⏱ 2mℹ️ Source: PYQ_2023

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