Physics - Geometrical Optics Question with Solution | TestHub

I1 from the lens: u = -25 cm, f = +20 cm, so $\frac{1}{v}-\frac{1}{u}=\frac{1}{f}\Rightarrow v=+100\mathrm{cm}$. I2 from the mirror: I1 acts as the object at u = -(120 - 100) = -20 cm, f = -15 cm, so $v=-60\mathrm{cm}$. I3 from the lens again: u = -60 cm, f = +20 cm, so $v=+30\mathrm{cm}$. The final image is formed on the other side of the lens, so it is real; the net magnification is negative, so it is inverted. Hence (C).