Physics - Geometrical Optics Question with Solution | TestHub

Given, $\mathrm{A}=60^{\circ },{\delta }_{\mathrm{m}}=30^{\circ }$ According to prism formula, $\mu =\frac{\sin \left(\frac{A+{\delta }_{\mathrm{m}}}{2}\right)}{\sin \left(\frac{\mathrm{A}}{2}\right)}$ or $\mu =\frac{\sin \left(\frac{60^{\circ }+30^{\circ }}{2}\right)}{\sin \frac{60^{\circ }}{2}}=\frac{\sin 45^{\circ }}{\sin 30^{\circ }}$ or $\mu =\sqrt{2}$ $\begin{array}{rl}\because \mu & =\frac{\text{ Speed of light in air (c) }}{\text{ Speed of light in prism (v) }}\\ v& =\frac{\mathrm{c}}{\mu }=\frac{3\times 10^8}{\sqrt{2}}=\frac{3}{\sqrt{2}}\times 10^8\mathrm{m}/\mathrm{s}\end{array}$